# Friday February 21st Question: how do we define $h_{V, D}$? Answer: write $D = D_1 - D_2$ which are (very) ample divisors and basepoint free. We then obtain embeddings \begin{align*} \varphi_1: V &\injects \PP_K^{n_1} \\ \varphi_2: V &\injects \PP_K^{n_2} .\end{align*} So write $$ h_{V, D}(p) = h(\varphi_1(p)) - h(\varphi_2(p)) + O(1) $$ Example : For $E/K$ an elliptic curve, - $2[0]$ is an ample divisor - $3[0]$ is a very ample divisor. Let $K$ be a local field (i.e. $\CC, \RR,$ a $p\dash$adic field, or $\FF_q((t))$ formal Laurent series) and $A/K$ be an abelian variety; we want to understand $A(K)$. We know this has the structure of compact abelian $K\dash$analytic Lie group. - Question 1: What does Lie theory say? - Question 2: What extra information comes from $A/K$ being a $g\dash$dimensional abelian variety? If $K = \CC$, then $A(K) \cong (\RR/\ZZ)^{2g}$. If $K = \RR$, then $A(K) \cong (\RR/\ZZ)^g \oplus \prod_{i=1}^d \ZZ/2\ZZ$ where $0\leq d \leq g$. Fix $d$, then - Let $E_1/\RR$ with $\Delta > 0$ (and thus 3 real roots), then $E_1(\RR)[2] = \qty{\ZZ/2\ZZ}^2$. - Let $E_2/\RR$ with $\Delta < 0$ (and 1 real root), then $E_2(\RR)[2] = \ZZ/2\ZZ$. By taking products of $E_1$ and $E_2$, i.e. $A =(E_1)^{d} \cross (E_2)^{g-d}$. > Todo: find reference in Silverman? Fact : $A(K)$ is totally disconnected and homeomorphic to a Cantor set. Fact (From Lie Theory, Serre p.116) : If $G$ is an abelian compact $K\dash$analytic Lie group, then there exists a filtration by open finite index subgroups $$ G = G^0 \supset G^1 \supset \cdots \supset G^n \supset \cdots $$ such that 1. The successive quotients are finite, and each $G^i$ is *standard*, i.e. obtained by evaluating a formal group law on $\qty{\mfm^i}^g$. 2. $\intersect_i G^i = (0)$. 3. $G^i / G^{i+1}$ has exponent $p$, i.e. it is a finite dimensional $\ZZ/p\ZZ\dash$vector space. 4. $G'[\tors] = G'[p^\infty]$, all of the prime-to-$p$ torsion is $p\dash$primary. > Todo: define $p\dash$primary torsion, $\QQ_p$. What structure theorem does this give? Theorem (C-Lacy) : Let $G$ be a compact, second countable, $K\dash$analytic abelian Lie group of dimension $g\geq 1$. Then a. If $\ch K = 0$ and $d = [K: \QQ_p]$, then $$ G \cong_{\text{TopGrp}} \ZZ_p^{dg} \oplus G[\tors] $$ where $G[\tors]$ is finite. b. If $\ch K = p$, i.e. $K = \FF_q((t))$, and if it is true that $G[\tors]$ is finite iff $G[p]$ finite, then $$ G \cong_{\text{TopGrp}} \prod_{i=1}^\infty \ZZ_p \oplus G[\tors] $$ For any $g\geq 1$, $(T, +)$ a finite discrete abelian group $(R, +) \cong (\ZZ_p^d, +)$ and $R^g \oplus T$ is a compact abelian $K\dash$analytic Lie group isomorphic to $\ZZ_p^{dg} \oplus T$ (?). > Question: what does this mean for $G = S^1$? Ask Pete! Theorem (Cartan) : Let $K$ be a local field, $\QQ\injects K$ dense (so $K = \RR, \QQ_p$). Then if $G_1, G_2$ are $K\dash$analytic, and $\varphi \in \hom_{\text{TopGrp}}(G_1, G_2)$, then $\varphi \in \hom_{k\dash\text{analytic}}(G_1, G_2)$. Example : For $R = \FF_q[[t]]$, $(R, +)^g [p] = (R, +)^g$. Example : Take $G = \GG_a^g(K)$ the additive group or $A/K$ a $g\dash$dimensional abelian variety (i.e. $G = A(K)$) then $G[p] \subsetneq (\ZZ/p\ZZ)^{2g}$ and is finite. ## Proof of Cartan's Theorem ### Step 1 We want to show that $G[p] < \infty$, then $G[\tors] < \infty$. We'll use the filtration in Serre's result; then for $i \gg 1$, we'll have $G^i[p] = 0$. Thus for $i \gg 1$, we'll have $G^i[p^\infty] = 0$; but this is the only torsion that can appear. We'll then obtain an injection $G[\tors] \injects G/G^i < \infty$. Lemma : Let $H$ be an abelian torsionfree pro$\dash p$ group (e.g. $\prod \ZZ_p$). Then $H \cong \prod_{i\in I} \ZZ_p$, and if $H$ is second-countable, then $I$ is countable. Proof : Omitted. Idea: use Pontrayagin duality $G\dual \definedas \hom_{\text{Top}}(G, \RR/\ZZ)$ for locally compact abelian groups. \ Use the fact that this is naturally an exact contravariant functor, this lets you trade in profinite groups for discrete torsion abelian groups. > Note: look up pro-p groups. Is the Pontrayagin dual a cohomotopy group?