1 Talk 1: Number Theory and 3-Dimensional Geometry

Abstract: There is a wonderful analogy between the theory of numbers, and 3-dimensional geometry. For example, prime numbers behave like knots!
I will explain some of the history of this analogy and how it is evolving.

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Mazur (63) observes similarity between the Alexander polynomial and Iwasawa’s polynomial. Both are pure group theory, and the construction arises from action of \(G^{\operatorname{ab}}\curvearrowright[G, G]^{\operatorname{ab}}\) and taking a characteristic polynomial. Analogies:

Analogies (partially) due to Mazur, guided by results of Artin and Tate.

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Defining \(G_p\): take all rings over \(k\) with some finite rank \(r\) which admit exactly \(r\) embeddings in \({ \mkern 1.5mu\overline{\mkern-1.5muk\mkern-1.5mu}\mkern 1.5mu }\), take their union, take ring automorphisms. Constructing such rings: find polynomials \(p\) with \({\operatorname{disc}}_p = p^k\) for some \(k\). Problem: \(G_p\) is very mysterious! Probably finitely generated but infinite, the only element we can produce is complex conjugation, \(z\mapsto \mkern 1.5mu\overline{\mkern-1.5muz\mkern-1.5mu}\mkern 1.5mu\). Tate (62) shows that \(G_p\) cohomologically looks like a knot group, currently the strongest formal analogy.

warnings:

Fixing a specific prime \(p\), it is not analogous to any specific not, and \({\mathbb{Z}}\) is not analogous to any specific manifold. Instead, there is some unknown refinement which recovers properties of both.

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Idea: compare statistical properties of random knots vs random primes.

question:

If \({\mathbb{Z}}\sim M^3\) and \(p\sim K_p \hookrightarrow M^3\), what object is analogous to \(K^c\)?

2 Talk 2: Symplectic L-functions and their topological analogues

Abstract: The topology of the symplectic group enters into many different areas of mathematics. After discussing a couple of “classical” manifestations of this, I will explain a new one, in the theory of L-functions, as well as a purely topological analogue of the statement. I am not going to assume any familiarity with the theory of L-functions for the talk. Joint work with Amina Abdurrahman.

2.1 Symplectic Spaces

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Note: for \(L\) a field, \begin{align*} { {L}_{\scriptscriptstyle \square} } \mathrel{\vcenter{:}}=\left\{{a^2 {~\mathrel{\Big\vert}~}a\in L}\right\} .\end{align*}

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Recall that any symplectic vector space is isomorphic to \(\qty{{\mathbb{R}}^{2g}, J\mathrel{\vcenter{:}}={ \begin{bmatrix} {0} & {\operatorname{id}_g} \\ {- \operatorname{id}_g} & {0} \end{bmatrix} }}\). Write \begin{align*} {\operatorname{SP}}(V) = \left\{{g: V\to V{~\mathrel{\Big\vert}~}{\left\langle {gx},~{gy} \right\rangle} = {\left\langle {x},~{y} \right\rangle}}\right\} = \left\{{A\in \operatorname{GL}_{2g}({\mathbb{R}}) {~\mathrel{\Big\vert}~}A^tJA = J}\right\} .\end{align*} Note \begin{align*} {\operatorname{SP}}_2({\mathbb{R}}) = \left\{{M\in \operatorname{GL}_2({\mathbb{R}}) {~\mathrel{\Big\vert}~}\operatorname{det}M = 1}\right\} ,\end{align*} and \({\operatorname{SP}}_{2g}({\mathbb{R}})\) is connected but \({\operatorname{SP}}_{2g}({\mathbb{R}}) \simeq{\mathbb{R}}^2\setminus\left\{{0}\right\}\). Let \(p: G\to {\operatorname{SP}}_{2g}({\mathbb{R}})\) be the universal cover; since the base is a topological group, picking any \(p^{-1}(1)\) yields an essentially unique group structure on \(G\) by analytically continuing the group law. In fact \(G\) is a Lie group and \(\ker p \cong {\mathbb{Z}}\in Z(G)\) is central, so there is a SES \begin{align*} {\mathbb{Z}}\to G\to {\operatorname{SP}}_{2g}({\mathbb{R}}) .\end{align*} Note that there are not faithful finite-dimensional reps of \(G\), but there are infinite-dimensional reps important to quantization in physics.

2.2 Surfaces

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A theorem of Meyer on surfaces: let \(\Sigma\) be a (compact closed oriented smooth) surface and \(\rho: \pi_1 \Sigma\to {\operatorname{SP}}_{2g}{\mathbb{R}}\); this corresponds to a local system, so form the twisted cohomology \(H^1(\Sigma; \rho)\). Using the cup product and symplectic pairing, one can produce a symmetric pairing \begin{align*} L: H^1(\Sigma;\rho){ {}^{ \scriptstyle\otimes_{{\mathbb{R}}}^{2} } }\to {\mathbb{R}} .\end{align*} There is an isomorphism \((H^1, L)\cong ({\mathbb{R}}^{p+q}, \operatorname{diag}_{p}(-1) \oplus \operatorname{diag}_q(1))\), so \(\operatorname{sig}(\Sigma, \rho) \mathrel{\vcenter{:}}=\operatorname{sig}L \mathrel{\vcenter{:}}= p-q\) is an interesting invariant.

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Recall that 4-manifolds \(M\) also admit a signature on \(H^2(M; {\mathbb{R}})\). Let \(M\to\Sigma\) be surface bundle over a surface – if \(M\) is a product, \(\operatorname{sig}M = 0\). Chern-Hirzebruch-Serre: there is a monodromy morphism \(\pi_1\Sigma\to {\operatorname{SP}}_{2g}{\mathbb{R}}\) which is trivial if \(\operatorname{sig}M = 0\). In fact \(\operatorname{sig}(M) = \operatorname{sig}(\Sigma, \rho)\), so this situation naturally arises for fibered 4-manifolds.

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Recall \(\pi_1 \Sigma_g = \left\langle{a_i,b_i {~\mathrel{\Big\vert}~}\prod_i [a_i, b_i] = e}\right\rangle\). Consider trying to form a lift:

Link to Diagram

Note \(m\mathrel{\vcenter{:}}=\prod [\tilde\rho a_i, \tilde\rho b_i] \in \ker p \cong {\mathbb{Z}}\), and it turns out that \begin{align*} \operatorname{sig}(\Sigma, \rho) = p-q = 4m .\end{align*} The fact that \(\ker p \in Z(G)\) was essential in making sure this doesn’t depend on choices. Note that this only determines \(m\) up to sign!

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Toward generalizing, the above central extension determines a class \(b\in H^2({\operatorname{SP}}_{2g}({\mathbb{R}}); {\mathbb{Z}})\) and \(p^* b\in H^2( \Sigma; {\mathbb{Z}})\). Using the pairing against the fundamental class \([\Sigma]\) yields \begin{align*} \operatorname{sig}(\Sigma, \rho) = 4 \int_\Sigma p^* b .\end{align*}

When replacing \({\mathbb{R}}\) with \(L\), replace \({\mathbb{Z}}\) by \(W_L\), the Witt group of quadratic forms over \(L\).

3 3-manifolds

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Consider now varying the situation in a 1-dimensional family – take \(\Sigma\to M\to S^1\) a surface bundle over a circle with fibers \(\Sigma_t\), each yielding \(\rho_t: \pi_1\Sigma_t \to {\operatorname{SP}}_{2g}({\mathbb{R}})\) for \(t\in S^1\). Each \(t\) yields a quadratic vector space \(H^1(\Sigma_t,\rho_t)\) of signature \((p, q)\). Monodromy yields an element \(m\in \mathop{\mathrm{Aut}}H^1(\Sigma_0, \rho_0) \subseteq {\operatorname{O}}_{p, q}\). If \(p,q>0\) then \({\sharp}\pi_0{\operatorname{O}}_{p, q} = 4\) – which connected component does this land in? How to separate the components: there is a determinant map \begin{align*} \operatorname{det}: {\operatorname{O}}_{p, q} \to \left\{{\pm 1}\right\} .\end{align*} There is a spinor norm \begin{align*} {\mathrm{spinornorm}}: {\operatorname{O}}_{p, q} &\to \left\{{\pm 1}\right\} = {\mathbb{R}}^{\times}/{ {{\mathbb{R}}}_{\scriptscriptstyle \square} }^{\times}\\ \mathrm{reflection}_v &\mapsto {\left\langle {v},~{v} \right\rangle} .\end{align*} This works with \({\mathbb{R}}\) replaced by \(L\), using the fact that \({\operatorname{O}}_{p, q}\) is generated by reflections. For \((V, L)\) a symmetric space, one gets \begin{align*} \operatorname{det}: {\operatorname{O}}(V) &\to \left\{{\pm 1}\right\} \end{align*} and \begin{align*} {\mathrm{spinornorm}}: {\operatorname{O}}(V) &\to L^{\times}/{ {L}_{\scriptscriptstyle \square} }^{\times} .\end{align*}

theorem (?):

It turns out that

Note that there is a Soulé etale Chern class \begin{align*} m\in H^3({\operatorname{SP}}_{2g}(L), L^{\times}/{ {L}_{\scriptscriptstyle \square} }^{\times}) .\end{align*} Pulling this back and integrating yields \begin{align*} p^* c\in H^3(M; L^{\times}/{ {L}_{\scriptscriptstyle \square} }^{\times}) \xrightarrow{\int_M} L^{\times}/{ {L}_{\scriptscriptstyle \square} }^{\times} .\end{align*}

proof (?):

Re-interplay \({\mathrm{spinornorm}}(m)\) as a quantity \({\mathrm{RT}}(M, \rho)\) where \({\mathrm{RT}}\) is the Reidemeister torsion, which makes sense for any \((M, \rho)\) (not just those fibered over \(S^1\)). This is a bordism invariant, i.e. if \(M\sim N\) are bordant then \({\mathrm{RT}}(M,\rho) = {\mathrm{RT}}(N,\rho')\). Thus there exists some formula of the desired type, where \(c\) is unknown – the trick is to compute enough examples to determine \(c\).

3.1 Symplectic \(L{\hbox{-}}\)functions

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For \(X\in{\mathsf{sm}}\mathop{\mathrm{proj}}{\mathsf{Var}}_{/ {{\mathbb{F}}_q}}\) and \(\rho: \pi_1 X\to {\operatorname{SP}}_{2g} k\) for \(k\) finite containing \(\sqrt{q}\), there is an associated \(L{\hbox{-}}\)function \(L(X, \rho; T)\in k(T)\) where \(T\approx q^{-s}\). There is a functional equation relating \(T\rightleftharpoons{1\over qT}\). Evaluate at the center of symmetry \(T = {1\over\sqrt q}\) to define \(L(X, \rho) \mathrel{\vcenter{:}}= L(X, \rho; 1/\sqrt q)\).

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Suppose \(L(X, \rho) \neq 0\); then modulo squares \begin{align*} L(X, \rho) = \int_X \rho^* c \qquad \in k^{\times}/{ {k}_{\scriptscriptstyle \square} }^{\times} ,\end{align*} which is a spinor norm of Frobenius (see Zassenhaus). This requires some conditions, e.g. \(\rho\mathrel{\Big|}_{\pi_1 X}\) is surjective, congruences on \({\sharp}k\) and \(q\operatorname{mod}8\), and \(\gcd(q,{\sharp}{\operatorname{SP}}_{2g}(k)) = 1\) (which may not be necessary).

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Interpretation: \(L(X,\rho) = ab^2\) where \(a\) is simple and \(b\) is complicated. BSD gives a conjectural formula for this which includes a lot of squares. So there is a cohomological obstruction to the existence of a square root of \(L(X, \rho)\).

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On the proof: try to pass validity from one known example \((X,\rho)\) to other examples \((X', \rho')\) with \(X_{/ {{\mathbb{F}}_q}} , X'_{/ {{\mathbb{F}}_q'}}\) and images in \({\operatorname{SP}}_{2g}(k), {\operatorname{SP}}_{2g}(k')\) respectively.

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Final comparison:

4 Talk 3: Relative Langlands Duality

Abstract: If we are given a compact Lie group G acting on a space X, a powerful tool in “approximately” decomposing the G-action on functions on X is the orbit method. I will describe this method and how it sometimes refines to an exact algebraic statement which involves a “dual” group G^ and dual space X^. This is part of a joint work with David Ben-Zvi and Yiannis Sakellaridis about duality in the relative Langlands program. I will do my best to make the talk comprehensible without any familiarity with the framework of the Langlands program.

5 Bibliography