# Finite-dimensional Semisimple Lie Algebras over $\CC$ (Wednesday, August 17) ## Humphreys 1.1 :::{.remark} Main goal: understand semisimple finite-dimensional Lie algebras over $\CC$. These are extremely well-understood, but there are open problems in infinite-dimensional representations, representations over other fields, and Lie superalgebras. ::: :::{.remark} Recall that an associative algebras is a ring with the structure of a $k\dash$vector space, and *algebra* generally means a non-associative algebra. Given any algebra, one can define a new bilinear product \[ [\wait, \wait]: A\tensor_k A &\to A \\ a\tensor b &\mapsto ab-ba \] called the **commutator bracket**. This yields a new algebra $A_L$ which is an example of a Lie algebra. ::: :::{.definition title="Lie algebra"} For $L\in \mods{\FF}$ with an operation $[\wait, \wait]: L\times L\to L$ (called the **bracket**) is a **Lie algebra** if 1. $[\wait,\wait]$ is bilinear, 2. $[x, x] = 0$ for all $x\in L$, and 3. the Jacobi identity holds: $[x[yz]] + [y[zx]] + [z[xy]] = 0$. ::: :::{.exercise title="?"} Check that $[ab]\da ab-ba$ satisfies the Jacobi identity. ::: :::{.remark} \envlist - Expanding $[x+y, x+y] = 0$ yields $[xy] = -[yx]$. Note that this is equivalent to axiom 2 when $\characteristic \FF\neq 2$ (given axiom 1). - The Jacobi identity can be rewritten as $[x[yz]] = [[xy]z] + [y[xz]]$, where the second term is an error term measuring the failure of associativity. Note that this is essentially the Leibniz rule. ::: :::{.definition title="Abelian Lie algebras"} A Lie algebra $L\in\Lie\Alg\slice\FF$ is **abelian** if $[xy]=0$ for all $x,y\in L$. ::: :::{.definition title="Morphisms of Lie algebras"} A **morphism** in $\Lie\Alg\slice\FF$ is a morphism $\phi\in \mods{\FF}(L, L')$ satisfying $\phi( [xy] ) = [ \phi(x) \phi(y) ]$. ::: :::{.exercise title="?"} Check that if $\phi$ has an inverse in $\mods{\FF}$, then $\phi$ automatically has an inverse in $\Lie\Alg\slice \FF$. ::: :::{.definition title="Subobjects"} A vector subspace $K\leq L$ is a **Lie subalgebra** if $[xy]\in K$ for all $x,y\in K$. ::: :::{.remark} \envlist - Note that any nonzero $x\in L$ determines a 1-dimensional Lie subalgebra $K\da \FF\cdot x$, which is in fact abelian. - A big source of Lie algebras: left-invariant vector fields on a Lie group. - We'll restrict to finite-dimensional algebras for the remainder of the class. ::: ## Humphreys 1.2: Linear Lie Algebras :::{.remark} For $V\in \mods{\FF}$, the endomorphisms $A\da \Endo_\FF(V)$ is an associative algebra over $\FF$. Thus it can be made into a Lie algebra $\liegl(V) \da A_L$ by defining $[xy] = xy-yx$ as above. ::: :::{.definition title="Linear Lie algebras"} Any subalgebra $K\leq \liegl(V)$ is a **linear Lie algebra**. ::: :::{.remark} After picking a basis for $V$, there is a noncanonical isomorphism $\Endo_\FF(V) \cong \Mat_{n\times n}(\FF)$ where $n\da \dim_\FF V$. The resulting Lie algebra is $\liegl_n(\FF) \da \Mat_{n\times n}(\FF)_L$. ::: :::{.fact} By Ado-Iwasawa, any finite-dimensional Lie algebra is isomorphic to some linear Lie algebra. ::: :::{.example title="?"} The upper triangular matrices form a subalgebra $\liet_n(\FF) \leq \liegl_n(\FF)$.[^commutator_triangle] This is sometimes called the Borel and denoted $\lieb$. There is also a subalgebra $\lien_n(\FF)$ of strictly upper triangular matrices. The diagonal matrices form a maximal torus/Cartan subalgebra $\lieh_n(\FF)$ which is abelian. [^commutator_triangle]: You get something interesting if you take the commutator bracket of two upper triangular matrices. ::: :::{.example title="Classical Lie algebras"} \envlist - Type $A_n \leadsto \liesl_{n+1}(\FF)$ is the special linear Lie algebra, traceless matrices. - Type $B_n \leadsto \lieso_{2n+1}(\FF)$ is the odd orthogonal Lie algebra. - Type $C_n \leadsto \liesp_{2n}(\FF)$ is the symplectic Lie algebra. - Type $D_n \leadsto \lieso_{2n}(\FF)$ is the even orthogonal Lie algebra. - The remaining 3 are defined by matrices satisfying $sx = -x^t s$ where $s$ is one of the following: - $\mattt 1 0 0 0 0 {I_n} 0 {I_n} 0$ corresponding to $\lieso_{2n+1}$, - $\matt 0 {I_n} {-I_n} 0$ corresponding to $\liesp_{2n}$, - $\matt 0 {I_n} {I_n} 0$ corresponding to $\lieso_{2n}$. These can be viewed as the matrices of a nodegenerate bilinear form: writing $N$ for the size of the matrices, the matrices act on $V \da \FF^N$ by a bilinear form $f: V\times V\to \FF$ given by $f(v, w) = v^t s w$. The form will be symmetric for $\lieso$ and skew-symmetric for $\liesp$. The equation $sx=-x^ts$ is a version of preserving the bilinear form $s$. Note that these are the Lie algebras of the Lie groups $G = \SO_{2n+1}(\FF), \Symp_{2n}(\FF), \SO_{2n}(\FF)$ defined by the condition $f(gv, gw) = f(v, w)$ for all $v,w\in \FF^N$ where $G = \ts{g\in \GL_N(\FF) \st f(gv, gw) = f(v, w)}$. This is equivalent to the condition that $f(gv, w) = f(v, g\inv w)$. ::: :::{.remark} Philosophy: $G\to \lieg$ sends products to sums. \todo{Check, might have gotten this backward.} ::: :::{.exercise title="?"} Check that the definitions of $\SO_n(\FF), \Symp_n(\FF)$ yield Lie algebras. :::